java - Sorted int[] Converted from String[] -- ArrayIndexOutOfBoundsException -

context

i've been trying fix part of program while without success. want sort string [] each element in format: name:number (i.e. john:32).

progress

so far, code splits each element , adds equivalent int []. attempt compare elements in int [] selection sort , swap elements in string [].

problem

i'm getting java.lang.arrayindexoutofboundsexception string [], called scores. why this?

scores = sort(scores); //arrayindexoutofboundsexception here   public static string [] sort(string [] a) {           //equivalent array containing integer part of score[i]         int[] temparray = new int[a.length];          //populate temparray         for(int = 0; < a.length; i++) {             //acquire numerical part of element             //arrayindexoutofboundsexception here********             int num = integer.parseint(a[i].split(":")[1]);              //add array             temparray[i] = num;         }           /* selection sort: descending */          //compare elements (integer) in temparray         for(int = 0; < temparray.length; i++){         int index = i;               //search integers larger above index                 for(int j = i+1; j < temparray.length; j++ ){                     if(temparray[j] > temparray[index]){                         index = j;                     }}                  //swap elements in scores-array (string)                 string temp = a[index];                 a[index] = a[i];                 a[i] = temp;         }          return a;     } 

i agree @shmosel

this can rooting out bad apple

string scoresplit[] = a[i].split(":"); if (scoresplit.length() == 2){    int num = integer.parseint(a[i].split(":")[1]); } else{    system.out.println("bad apple "+ scoresplit[0]);  //some kind of logging }