Recursion java - Testing is the sum of the two Integers are equal Boolean function -

i have write recursive function accepts 2 integers. function returns true if first number digit amount equal second number, otherwise function returns false.

the function return true.

what doing wrong?

the code:

public static boolean amountequal(int num1, int num2) {     int sum1 = 0, sum2 = 0;      if (num1 == 0 && num2 == 0 && sum1 == sum2)         return true;     else if (num1 == 0 && num2 == 0 && sum1 != sum2)         return false;      sum1 += num1 % 10;     sum2 += num2 % 10;      return amountequal(num1 / 10, num2 / 10); } 

thank's

what doing wrong?

you using sum zero. need figure out way pass sum1 , sum2 along, final invocation make decision based on prior invocations.

one way of doing making recursive function 4 parameters, , adding two-parameter overload start recursive chain:

public static boolean amountequal(int num1, int num2) {     return amountequal(num1, num2, 0, 0); } private static boolean amountequal(int num1, int num2, int sum1, int sum2) {     ... // recursive code goes here } 

another approach compute digit differential, i.e. sum of digits in num1 minus sum of digits in num2, , return true if differential zero:

public static boolean amountequal(int num1, int num2) {     return digitdifferential(num1, num2) == 0; } private static int digitdifferential(int num1, int num2) {     return (num1 != 0 || num2 != 0)     ? num1%10 - num2%10 + digitdifferential(num1/10, num2/10)     : 0; }