bash - Shell script creates linux user account but password goes wrong -

i've written shell script create user accounts. script reads user account name , password text file , create account info. when execute script creates accounts, when try log in accounts can't log in due invalid password, please try again error.

here script used create user accounts:

file_name="t.txt"  while read user pass     useradd -p ${pass} ${user} done < $file_name 

edit-1: t.txt file contains user account information: space separated username , password per line. here snippet of file:

user1 abcxyz user2 defxyz user3 ijklmn 

edit-2: when follow method recommended steve kline shows me following result: (still created accounts can't logged in given password)

passwd: unrecognized option '--stdin' usage: passwd [options] [login]  options:   -a, --all                     report password status on accounts   <---------------------------------- skipped ------------------------------->   -x, --maxdays max_days        set maximum number of days before password                                 change max_days  adding user user1  password  abcxyz123 

still created accounts can't logged in given password

so current method adding plaintext passwords /etc/shadow.

using script is... created this. mind you, added few digits @ end of password match standard 8 characters suppress "are sure" prompts.

user1:abcxyz123:16963:0:99999:7::: user2:defxyz142:16963:0:99999:7::: user3:ijklm1564:16963:0:99999:7::: 

the users files

[root@localhost ~]# cat t.txt s.txt user1 abcxyz123 user2 defxyz142 user3 ijklm1564 user4 abcxyz123 user5 defxyz142 user6 ijklm1564 

the script

#!/bin/bash -e #adding user1, user2, user3 using method. file_name="t.txt" while read user pass     #useradd ${user} -p ${pass}     useradd -p ${pass} ${user}     echo "adding user "${user}"  password  "${pass} done < $file_name  #adding user4, user5, user6 using recommended method. file_name="s.txt" while read user pass     #useradd ${user} -p ${pass}     useradd ${user}     echo "${pass}" | passwd --stdin ${user}     echo "adding user "${user}"  password  "${pass}  done < $file_name 

using both syntaxes, produced these results in /etc/shadow

user1:abcxyz123:16963:0:99999:7::: user2:defxyz142:16963:0:99999:7::: user3:ijklm1564:16963:0:99999:7::: user4:$1$npazyqan$tlhfqllp0cafiuenek8hw.:16963:0:99999:7::: user5:$1$4z8g4gvh$v0jzcv5xbhwixu1lg9mww.:16963:0:99999:7::: user6:$1$cbkcyjkj$7a.j6e3gy/umucvmy0tgt0:16963:0:99999:7::: 

so, therefor method posted works. update: ubuntu working method below. stdin confirmed rhel based systems.

useradd ${user} echo "${pass}" | passwd --stdin ${user} 

if heart absolutely set on using method, suggest installing mkpasswd , using syntax.

 useradd -p $(mkpasswd ${pass}) ${user} 

update ubuntu passwd stdin

echo ${user}:${pass} | /usr/sbin/chpasswd